Then show that a2 – 4a+ 7i 0. hence find a5
Splet23. mar. 2024 · Find the adjoint of the matrix A = (A.I.C.B.S.E. 2010) Solution: Here A = Now A 11 = Co-factor of 2 = 3, A 12 = Co-factor of – 1 = – 4, A 21 = Co-factor of 4 = 1 and … Splet30. mar. 2024 · Calculating A2 A2 = A.A = [ 8 (3& 1@ −1&2)] [ 8 (3& 1@ −1&2)] = [ 8 (3 (3)+1 (−1)&3 (1)+1 (2)@−1 (3)+2 (−1)&−1 (1)+2 (2))] = [ 8 (9−1& 3+2@ −3−2&−1+4)] = [ 8 (8& …
Then show that a2 – 4a+ 7i 0. hence find a5
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SpletYou have to show that any matrix that satisfies the equation A 2 + 2 A + I = 0 is invertible. – 5xum Mar 2, 2014 at 22:49 Add a comment 5 Answers Sorted by: 4 The inverse of A is almost certainly not A. You have A 2 + 2 A = − I, or A ( A + 2 I) = − I. Multiplying by − 1 you get A ( − A − 2 I) = I Hence the inverse of A is − A − 2 I. Share Cite Splet6. [25 marks] Consider the linear system of equations 4-4. 2 0-2 2. 099 7 4-1. 7 4 x 1 x 2 x 3 = 4. 2 4. 901 5. 7 . (1) (a) Evaluate an accurate solution to (1). You may use Python’s …
SpletIf A=[ 3−112], show that A 2−5A+7I=0. Hence, find A −1. Medium Solution Verified by Toppr We have, [ 3−112] ∴A 2=AA= [ 3−112][ 3−112]=[ 8−553] So, A 2−5A+7I= [ 8−553]−5[ … Splet03. apr. 2024 · a 2 + 8 = 4a Formula used: (a + b) 2 = a 2 + b 2 + 2ab Calculation: a 2 + 8 = 4a Squaring on both side ⇒ (a 2 + 8) 2 = (4a) 2 ⇒ a 4 + 16a 2 + 64 = 16a 2 ⇒ a 4 = – 64 ----1 a …
SpletQ. Suppose a Matrix A satisfies A2−5A+7I=0 If A5 =aA+bI, then the values of 2a + b is. Q. Show that A=[ 5 3 −1 −2] satisfies the equation A2 - 3A - 7I = 0 and hence find the value of A−1. Q. If A2 =3A−2I and A8 =aA+bI, then a+b is Q. For the matrix A=[3 2 1 1], the values of a and b such that A2+aA+bI=0 are View More SpletThen show that A 2 – 4A + 7I = O. Using this result calculate A 5 also. Advertisement Remove all ads Solution We have A 2 = [ 2 3 - 1 2] [ 2 3 - 1 2] = [ 1 12 - 4 1] – 4A = [ - 8 - 12 …
Splet19. jan. 2024 · Show that `A =[{:(5,3),(-1,-2):}]` satisfies the equation `A^(2)-3A-7I=0` and hence find the value of `A^(-1)`
Splet30. avg. 2024 · Best answer We have, Therefore, A2 – 4A + 7I A2 = 4A – 7I Thus A3 = A.A2 = A (4A – 7I) = 4 (4A – 7I) – 7A = 16A – 28I – 7A = 9A – 28I and so A5 = A3A2 = (9A – … mouth to mouth propagandaSplet30. apr. 2024 · Here your question is "prove that A has an inverse ". For this you have to show that d e t ( A) ≠ 0. Now since A satisfies the polynomial equation x 2 − 3 x + 1 = 0 … heat connectSpletYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Let A be an (n × n) matrix which satisfies the equation A2 ? 2A + I = … heat consumption used by police buildingSpletA 2 = 1 12 -4 1-4A = -8 -12 4 -8 7I = 7 0 0 7 add these three values u will get 0. 0 mouth to mouth respiration historySplet04. nov. 2024 · Hence Solve the system of equations; x - 2y = 10 2x - y - z = 8 -2y + z = 7 class-12 Share It On 1 Answer +2 votes answered Nov 4, 2024 by Darshee (49.8k points) selected Nov 16, 2024 by Aanchi Best answer A = 1 (−1 − 2) − 2 (−2 − 0) = −3 + 4 = 1 A is non-singular, therefore A−1 exists The given equations can be written as: mouth to mouth respiration is calledSpletQuestion From - NCERT Maths Class 12 Chapter 3 MISCELLANEOUS EXERCISE Question – 8 MATRICES CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-If `A=[3 1-1 2]` , ... heat consumption formulaSpletNow, A 2−4A+7I=[ 1−4121]−4[ 2−132]+7[1001] = [ 1−4121]−[ 8−4128]+[7007]=[0000]=0(zeromatrix) ⇒ A 2−4A+7I=0 ⇒ A 2=4A−7I. ⇒ A⋅A 2=4A⋅A−7AI … mouth to mouth publicity