WebRounding down, the largest positive integer of N is 17, then 306 / 17 = 18, which happens to be two consecutive integers that meet the requirements, so the answer to first question are 17 and 18. Another question: why round down instead of up? In fact, it is very simple. Web8 rows · Example: Find two consecutive positive integers sum of whose squares is 365. Solution: ...
SOLUTION: The product of two consecutive even positive integers is …
WebFind two consecutive positive integers, sum of whose squares is 365. Easy Solution Verified by Toppr Let the consecutive numbers be x,x+1 Sum of their squares x 2+(x+1) … WebThe difference between two consecutive integers is always equal to 1. For any given integer n, the formula to get a consecutive integer is n + 1, where “n” can be any integer. Thus, the sum of two consecutive integers n … lawrence cooper attorney
SOLUTION: THE PRODUCT OF TWO CONSECUTIVE …
WebFeb 24, 2024 · To find two consecutive odd integers, you need to: Denote the smallest of them by 2x + 1. Write the next integer as 2x + 3. If needed, use the representation to describe the integers' properties. Use the algebraic description to find the integers. … Using this formula, you can find the solutions to any quadratic equation. … WebTwo consecutive even positive integers, sum of the squares of which is 1060 are. A 16 and 18 B 12 and 14 C 22 and 24 D 20 and 22 Medium Solution Verified by Toppr Correct option is C) Let the two consecutive positive even integers be x and x+2. It is given that the sum of the squares of the integers is 1060, therefore, we have: WebNov 3, 2015 · The product of two consecutive even integers is 224. Find the integers Follow • 2 Add comment Report 1 Expert Answer Best Newest Oldest Chaoyun L. answered • 11/03/15 Tutor 1 (1) Master of Math with concentration in Statistics See tutors like this Let one integer be x, and the other be (x+2) x (x+2)=224 x 2 +2x-224=0 (x+16) (x-14) =0 x= … lawrence coots